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		<title>How to make XP go faster (Some tips that can help you to make your XP faster)</title>
		<link>http://topcodes.wordpress.com/2009/12/05/how-to-make-xp-go-faster-some-tips-that-can-help-you-to-make-your-xp-faster/</link>
		<comments>http://topcodes.wordpress.com/2009/12/05/how-to-make-xp-go-faster-some-tips-that-can-help-you-to-make-your-xp-faster/#comments</comments>
		<pubDate>Sat, 05 Dec 2009 17:06:49 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Miscellaneous]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/?p=139</guid>
		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 06/12/09 */ Here are some tips that can make your XP faster than before. Services You Can Disable : There are quite a few services you can disable from starting automatically. This would be to speed up [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=139&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<div>
<h2>/*</h2>
<p>Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 06/12/09<br />
*/</p>
<p>Here are some tips that can make your XP faster than before.</p>
<p><strong><span style="text-decoration:underline;">Services You Can Disable</span></strong> :</p>
<p>There are quite a few services you can disable from starting automatically.<br />
This would be to speed up your boot time and free resources.<br />
They are only suggestions so I suggest you read the description of each one when you run Services<br />
and that you turn them off one at a time.</p>
<p>Some possibilities are:<br />
1.   Alerter<br />
2.   Application Management<br />
3.   Clipbook<br />
4.   Fast UserSwitching<br />
5.   Human Interface Devices<br />
6.   Indexing Service<br />
7.   Messenger<br />
8.   Net Logon<br />
9.   NetMeeting<br />
10. QOS RSVP<br />
11. Remote Desktop Help Session Manager<br />
12. Remote Registry<br />
13. Routing &amp; Remote Access<br />
14. SSDP Discovery Service<br />
15. Universal Plug and Play Device Host<br />
16. Web Client</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<div><strong>Cleaning the Prefetch Directory</strong> :</p>
<p>WindowsXP has a new feature called Prefetch. This keeps a shortcut to recently used programs.<br />
However it can fill up with old and obsolete programs.</p>
<p>To clean this periodically go to:</p>
<p>Star / Run / Prefetch<br />
Press Ctrl-A to highlight all the shorcuts<br />
Delete them</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<p><strong>Not Displaying of Logon, Logoff, Startup and Shutdown Status Messages</strong> :</p>
<p>To turn these off:</p>
<p>Start Regedit<br />
Go to HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindowsCurrentVersionpoliciessystem<br />
If it is not already there, create a DWORD value named DisableStatusMessages<br />
Give it a value of 1</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
<strong>Clearing the Page File on Shutdown</strong> :</p>
<p>Click on the Start button<br />
Go to the Control Panel<br />
Administrative Tools<br />
Local Security Policy<br />
Local Policies<br />
Click on Security Options<br />
Right hand menu &#8211; right click on &#8220;Shutdown: Clear Virtual Memory Pagefile&#8221;<br />
Select &#8220;Enable&#8221;<br />
Reboot</p>
<p>For regedit users&#8230;..<br />
If you want to clear the page file on each shutdown:</p>
<p>Start Regedit<br />
Go to HKEY_LOCAL_MACHINESYSTEMCurrentControlSetControlSession ManagerMemory ManagementClearPageFileAtShutdown<br />
Set the value to 1</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<p><strong>No GUI Boot :</strong></p>
<p>If you don&#8217;t need to see the XP boot logo,</p>
<p>Run MSCONFIG<br />
Click on the BOOT.INI tab<br />
Check the box for /NOGUIBOOT</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br />
<strong>Speeding the Startup of Some CD Burner Programs</strong> :</p>
<p>If you use program other than the native WindowsXP CD Burner software,<br />
you might be able to increase the speed that it loads.</p>
<p>Go to Control Panel / Administrative Tools / Services<br />
Double-click on IMAPI CD-Burning COM Service<br />
For the Startup Type, select Disabled<br />
Click on the OK button and then close the Services window<br />
If you dont You should notice</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<p><strong>Getting Rid of Unread Email Messages</strong> :</p>
<p>To remove the Unread Email message by user&#8217;s login names:</p>
<p>Start Regedit<br />
For a single user: Go to HKEY_CURRENT_USERSoftwareMicrosoftWindowsCurrentVersionUnreadMail<br />
For all users: Go to HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindowsCurrentVersionUnreadMail<br />
Create a DWORD key called MessageExpiryDays<br />
Give it a value of 0</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;</p>
<p><strong>Decreasing Boot Time</strong> :</p>
<p>Microsoft has made available a program to analyze and decrease the time it takes to boot to WindowsXP<br />
The program is called BootVis</p>
<p>Uncompress the file.<br />
Run BOOTVIS.EXE<br />
For a starting point, run Trace / Next Boot + Driver Delays<br />
This will reboot your computer and provide a benchmark<br />
After the reboot, BootVis will take a minute or two to show graphs of your system startup.<br />
Note how much time it takes for your system to load (click on the red vertical line)<br />
Then run Trace / Optimize System<br />
Re-Run the Next Boot + Drive Delays<br />
Note how much the time has decreased<br />
Mine went from approximately 33 to 25 seconds.</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
<strong>Increasing Graphics Performance</strong> :</p>
<p>By default, WindowsXP turns on a lot of shadows, fades, slides etc to menu items.<br />
Most simply slow down their display.</p>
<p>To turn these off selectively:</p>
<p>Right click on the My Computer icon<br />
Select Properties<br />
Click on the Advanced tab<br />
Under Performance, click on the Settings button<br />
To turn them all of, select Adjust for best performance<br />
My preference is to leave them all off except for Show shadows under mouse pointer and Show window contents while dragging</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;</p>
<p><strong>Increasing System Performance</strong> :</p>
<p>If you have 512 megs or more of memory, you can increase system performance<br />
by having the core system kept in memory.</p>
<p>Start Regedit<br />
Go to HKEY_LOCAL_MACHINESYSTEMCurrentControlSetControlSession ManagerMemory ManagementDisablePagingExecutive<br />
Set the value to be 1<br />
Reboot the computer</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;</p>
<p><strong>Increasing File System Caching</strong> :</p>
<p>To increase the amount of memory Windows will locked for I/O operations:</p>
<p>Start Regedit<br />
Go to HKEY_LOCAL_MACHINESYSTEMCurrentControlSetControlSession ManagerMemory Management<br />
Edit the key IoPageLockLimit</p>
<p>&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;</p>
<p><strong>Resolving Inability to Add or Remove Programs</strong> :</p>
<p>If a particular user cannot add or remove programs, there might be a simple registry edit neeed.</p>
<p>Go to HKCUSoftwareMicrosoftWindowsCurrentVersionPoliciesUninstall<br />
Change the DWORD NoAddRemovePrograms to 0 disable it</p>
<p>4096 &#8211; 32megs of memory or less<br />
8192 &#8211; 32+ megs of memory<br />
16384 &#8211; 64+ megs of memory<br />
32768 &#8211; 128+ megs of memory<br />
65536 &#8211; 256+ megs of memory</p>
</div>
</div>
<div>Hope all these things will help you to make your XP faster.<br />
Best of Luck <img src='http://s0.wp.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </div>
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		<title>Printing numbers again&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;&#8230;.</title>
		<link>http://topcodes.wordpress.com/2009/11/18/printing-numbers-again/</link>
		<comments>http://topcodes.wordpress.com/2009/11/18/printing-numbers-again/#comments</comments>
		<pubDate>Wed, 18 Nov 2009 17:29:05 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Miscellaneous]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/?p=133</guid>
		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 18/11/09 */ Print the following as  output for a number n. Here the sample for n=5 1 121 12321 1234321 123454321 1234321 12321 121 1<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=133&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<div>
<h2>/*</h2>
<p>Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 18/11/09<br />
*/</p>
</div>
<p style="text-align:center;">Print the following as  output for a number n. Here the sample for n=5<br />
1<br />
121<br />
12321<br />
1234321</p>
<p style="text-align:center;">123454321</p>
<p style="text-align:center;">1234321</p>
<p style="text-align:center;">12321</p>
<p style="text-align:center;">121</p>
<p style="text-align:center;">1</p>
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		<title>Printing numbers&#8230;&#8230;&#8230;&#8230;.</title>
		<link>http://topcodes.wordpress.com/2009/11/17/printing-numbers/</link>
		<comments>http://topcodes.wordpress.com/2009/11/17/printing-numbers/#comments</comments>
		<pubDate>Tue, 17 Nov 2009 12:28:34 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Miscellaneous]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/2009/11/17/printing-numbers/</guid>
		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 17/11/09 */ Print the following as  output for a number n. Here the sample for n=5 1 121 12321 1234321 123454321<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=128&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p style="text-align:left;">/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 17/11/09<br />
*/</p>
<p style="text-align:center;">Print the following as  output for a number n. Here the sample for n=5<br />
1<br />
121<br />
12321<br />
1234321<br />
123454321</p>
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		<title>New Member Recruitment Notice</title>
		<link>http://topcodes.wordpress.com/2009/11/11/new-member-recruitment-notice/</link>
		<comments>http://topcodes.wordpress.com/2009/11/11/new-member-recruitment-notice/#comments</comments>
		<pubDate>Wed, 11 Nov 2009 13:13:36 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[1]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/2009/11/11/new-member-recruitment-notice/</guid>
		<description><![CDATA[A Programming Contest will be held in order to recruit new members for UIU Programming Contest Teams. The tentative date of Contest is after MID – II. Exact Date will be announced later. Basic knowledge of C Programming Language will be sufficient to solve all the problems. No Registration fee is required for participation. Individual [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=126&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A Programming Contest will be held in order to recruit new members for UIU Programming Contest Teams. The tentative date of Contest is after MID – II. Exact Date will be announced later. Basic knowledge of C Programming Language will be sufficient to solve all the problems. No Registration fee is required for participation.</p>
<ul>
<li>Individual 	Participant</li>
<li>Open 	Book Contest. You are allowed to bring your books/notes.</li>
<li>Refreshments 	will be available during contest period.</li>
<li>Preferred 	IDE :  Visual C &amp; Turbo C.</li>
<li>Internet 	connection will not be available.</li>
</ul>
<p>For more details &amp; Registration :</p>
<p>Moderator : Md. Faisal Kabir sir.<br />
Room # 116. Cell : 01712025763.</p>
<p>Sheikh Faiyaz Moorsalin.<br />
Cell : 01915472173.<br />
Email Id : <a href="mailto:sheikh303@gmail.com">sheikh303@gmail.com</a></p>
<p>Rafiul Sabbir.<br />
Cell : 01915686454.<br />
Email Id : <a href="mailto:oparthibo@gmail.com">oparthibo@gmail.com</a></p>
<p>Sajid Rabbani.<br />
Cell : 01817046667.<br />
Email Id : <a href="mailto:sjdrabbani@gmail.com">sjdrabbani@gmail.com</a></p>
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		<title>Graphs and Graph Theory</title>
		<link>http://topcodes.wordpress.com/2009/11/04/graphs-and-graph-theory/</link>
		<comments>http://topcodes.wordpress.com/2009/11/04/graphs-and-graph-theory/#comments</comments>
		<pubDate>Wed, 04 Nov 2009 14:51:29 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Topic Discussion]]></category>

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		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 04/11/09 */ In the branch of mathematics called Graph Theory, a graph bears no relation to the graphs that chart data, such as the progress of the stock market or the growing population of the planet. Graph [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=123&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 04/11/09<br />
*/</p>
<p>In the branch of mathematics called <strong>Graph Theory,</strong> a <strong>graph</strong> bears no relation to the graphs that chart data, such as the progress of the stock market or the growing population of the planet.  Graph paper is not particularly useful for drawing the graphs of Graph Theory.</p>
<p>In Graph Theory, a <strong>graph</strong> is a collection of dots that may or may not be connected to each other by lines.  It doesn&#8217;t matter how big the dots are, how long the lines are, or whether the lines are straight, curved, or squiggly.  The &#8220;dots&#8221; don&#8217;t even have to be round!</p>
<p><img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/graphex2.gif" alt="" /></p>
<p>All that matters is which dots are connected by which lines.</p>
<p>Two dots can only be connected by one line.  If two dots are connected by a line, it&#8217;s not &#8220;legal&#8221; to draw another line connecting them, even if that line stretches far away from the first one.</p>
<p>If you look at a graph and your eyes want to zip all around it like a car on a race course, or if you notice shapes and patterns inside other shapes and patterns, then you are looking at the graph the way a graph theorist does.</p>
<h2>Here are some of the special words graph theorists use to describe what they see when they are looking at graphs:</h2>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">1. Edges &amp; vertices of a graph :</span></p>
<p>A graph is made up of dots connected by lines.</p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/gredver.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgredver.gif" alt="" align="bot" /></a></p>
<p>A &#8220;dot&#8221; is called a vertex<strong> </strong>.</p>
<p>When there is more than one vertex, they are called vertices<strong> </strong>.</p>
<p>A &#8220;line&#8221; is called an edge<strong>.</strong> (The plural is simply edges)</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">2. The degree of a vertex in a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/degex1.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lildegex1.gif" alt="" align="bot" /></a></p>
<p>The <strong>degree</strong> of a vertex in a graph is the number of edges that touch it.</p>
<p>The number on each vertex of this graph is the degree of that vertex.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">3.  Size of a graph :</span></p>
<p>The <strong>size</strong> of a graph is the number of vertices that it has.</p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grsize.gif"><img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrsize.gif" alt="" /></a></p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">4.  Regular graphs :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grreg.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrreg.gif" alt="" align="bot" /></a></p>
<p>A graph is <strong>regular</strong> if every vertex has the same degree.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">5.  Paths &amp; cycles in a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grpath.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrpath.gif" alt="" align="bot" /></a></p>
<p>A <strong>path</strong> is a route that you travel along edges and through vertices in a graph.  All of  the vertices and edges in a path are connected to one another.</p>
<p>A <strong>cycle</strong> is a path which begins and ends on the same vertex.  A <strong>cycle</strong> is sometimes called a <strong>circuit</strong>.</p>
<p>The number of edges in a path or a cycle is called the <strong>length</strong> of the path.  Is the length of the path also the number of vertices?</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">6. A Hamiltonian path in a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grhampath.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrhampath.gif" alt="" align="bot" /></a></p>
<p>A <strong>hamiltonian path</strong> in a graph is a path that passes through every vertex in the graph exactly once.  A hamiltonain path does not necessarily pass through all the edges of the graph, however.</p>
<p>A hamiltonian path which ends in the same place in which it began is called a <strong>hamiltonian circuit</strong> or a <strong>hamiltonain cycle </strong>.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">7. An Eulerian path in a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/greuler.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgreuler.gif" alt="" align="bot" /></a></p>
<p>An <strong>eulerian path</strong> in a graph is a path that travels along every edge of the graph exactly once. An eulerian path might pass through individual vertices of  the graph more than once.</p>
<p>An eulerian path which begins and ends in the same place is called an <strong>eulerian circuit</strong> or an <strong>eulerian cycle</strong></p>
<p>&nbsp;</p>
<p><strong><span style="text-decoration:underline;">8. Planar graphs :</span></strong></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grplanar.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrplanar.gif" alt="" align="bot" /></a></p>
<p>A <strong>planar</strong> graph is a graph that can be drawn so that the edges<a href="http://wwwc3.lanl.gov/mega-math/gloss/graph/gredver.html"> </a>only touch each other where they meet at vertices.</p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grnplrep.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrnplrep.gif" alt="" align="bot" /></a></p>
<p>You can usually re-draw a <strong>planar</strong> graph so that some of the edges cross. Even so, it is still a planar graph. When it is drawn so that the edges cross, the drawing is called a <strong>non-planar representation</strong> of a planar graph.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">9. Non-planar graphs :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grcomplet5.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrcomplet5.gif" alt="" align="bot" /></a></p>
<p>The graph above is <strong>nonplanar</strong>.  No matter how you stretch the edges around, you cannot redraw the graph so that none of the edges cross each other between the vertices .</p>
<p>A non-planar graph should not be confused with a planar graph that just happens to be drawn in such a way that two or more edged cross. The graph below is a planar graph, but it is drawn here in a nonplanar representation.</p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grnplrep.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrnplrep.gif" alt="" align="bot" /></a></p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">10. Distance in a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grdist.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrdist.gif" alt="" align="bot" /></a></p>
<p>Distance in a graph isn&#8217;t measured in inches or kilmoters. This isn&#8217;t surprising, because you don&#8217;t do any measuring in inches or kilometers when you draw a graph in the first place.</p>
<p>Still, when you look at a graph, you can see how it might be possible to say that some vertices are closer together then others.</p>
<p>The <strong> distance</strong> between two vertices is a count of the number of edges along which you must travel to get from one of the verticesto the other.</p>
<p>If there is more than one path between two vertices, the number of edges in the <strong>shortest</strong> path is the distance.</p>
<p>The number of edges in a path is called the <strong>length</strong> of  the path.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">11. The diameter of a graph :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grdiam.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrdiam.gif" alt="" align="bot" /></a></p>
<p>The <strong>diameter</strong> of a graph is the longest distance you can find between two vertices.</p>
<p>When you are measuring distances to determine a graph&#8217;s diameter, recall that if 2 vertices have many paths of different distances connecting them, you can only count the shortest one.</p>
<p>An interesting problem in graph theory is to draw graphs in which both the degrees of the vertices  and the diameter of the graph are small.  Drawing the largest graphs possible that meet these criteria is an open problem .</p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grdegdia44.gif"><img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrdegdia44.gif" alt="" /></a> <a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grdegdia34.gif"><img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrdegdia34.gif" alt="" /></a></p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">12. Isomeric graphs :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/griso.gif"> </a></p>
<p>Two graphs are <strong>isomorphic</strong> if you can re-draw one of them so that it looks exactly like the other.</p>
<p>To re-draw a graph, it helps to imagine the edges as infinitely stretchable rubber bands.  You can move the vertices around and stretch the edges any way you like &#8212; as long as they don&#8217;t become disconnected.</p>
<p>Sometimes it is very hard to tell whether two graphs are isomorphic or not. In fact, no one knows a simple method for taking two graphs and determining quickly whether or not they are isomorphic.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">13.  Complete graphs :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grcomplet5.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrcomplet5.gif" alt="" align="bot" /></a> <a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grcomplet2.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrcomplet2.gif" alt="" align="bot" /></a> <a href="http://wwwc3.lanl.gov/mega-math/workbk/graph/grcomplet8.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/graph/lilgrcomplet8.gif" alt="" align="bot" /></a></p>
<p>In a <strong>complete</strong> graph,  every pair of vertices is connected by an edge .  It is impossible to add an edge to a complete graph because every possible edge has been drawn.</p>
<p>Complete graphs always have diameter <strong>1</strong>.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">14. Neighboring vertices in a graph :</span></p>
<p>In a graph, the <strong>neighbors</strong> of a vertex are all the vertices which are connected to that vertex by a single edge.</p>
<p>The distance between two vertices which are neighbors is always 1.</p>
<p>&nbsp;</p>
<p><span style="text-decoration:underline;">15. Dominating sets in graphs :</span></p>
<p><a href="http://wwwc3.lanl.gov/mega-math/workbk/dom/doexample.gif"> <img src="http://wwwc3.lanl.gov/mega-math/workbk/dom/lildoexample.gif" alt="" align="bot" /></a></p>
<p>In a graph, the <strong>neighbors</strong> of a vertex are all the vertices which are connected to that vertex by a single edge.  A <strong>dominating set</strong> for a graph is a set of vertices whose neighbors, along with themselves, constitute all the vertices in the graph.</p>
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		<title>The Pythagorean Theorem</title>
		<link>http://topcodes.wordpress.com/2009/11/01/the-pythagorean-theorem/</link>
		<comments>http://topcodes.wordpress.com/2009/11/01/the-pythagorean-theorem/#comments</comments>
		<pubDate>Sun, 01 Nov 2009 16:42:11 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Topic Discussion]]></category>

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		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 02/11/09 */ If you’ve been doing math for any period of time, you’ve probably run into a formula that looks like this: a2 + b2 = c2 This very useful bit of math is called the Pythagorean Theorem, named [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=112&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 02/11/09<br />
*/</p>
<p>If you’ve been doing math for any period of time, you’ve probably run into a formula that looks like this:</p>
<p style="text-align:center;"><em>a</em><sup>2</sup> + <em>b</em><sup>2</sup> = <em>c</em><sup>2</sup></p>
<p>This very useful bit of math is called the Pythagorean Theorem, named after Greek mathematician Pythagoras. Put into words, the above equation tells us that the sum of the square of the two legs of a right triangle equals the square of the hypotenuse (the longest side of a right triangle).</p>
<p>This formula has many potential uses. If you know the length of both legs, or one leg and the hypotenuse, of a right triangle, then you can solve for the missing side using the Pythagorean Theorem.</p>
<p>For example, we are given that <em>a</em> = 3 and <em>b</em> = 4. Let’s solve for <em>c</em>.</p>
<p style="text-align:center;">3<sup>2</sup> + 4<sup>2</sup> = <em>c</em><sup>2</sup></p>
<p style="text-align:center;">9 + 16 = <em>c</em><sup>2</sup></p>
<p style="text-align:center;">25 = <em>c</em><sup>2</sup></p>
<p style="text-align:center;"><img title="\sqrt{25}" src="http://s2.wordpress.com/latex.php?latex=%5Csqrt%7B25%7D&amp;bg=ffffff&amp;fg=000000&amp;s=0" alt="\sqrt{25}" /> = <em>c</em></p>
<p style="text-align:center;">5 = <em>c</em></p>
<p>You can also use the Pythagorean Theorem to prove whether or not a triangle is a right triangle. For this example, let’s have <em>a</em> = 5, <em>b</em> = 10, and <em>c</em>= 13.</p>
<p style="text-align:center;">5<sup>2</sup> + 10<sup>2</sup> = 13<sup>2</sup></p>
<p style="text-align:center;">25 + 100 = 169</p>
<p style="text-align:center;">125 = 169</p>
<p>Wait a second! 125 does not equal 169. Therefore, a triangle with sides 5, 10, and 13 is not a right triangle.</p>
<p>Let’s try it again with a triangle with the sides 7, 24, and 25.</p>
<p style="text-align:center;">7<sup>2</sup> +24<sup>2</sup> = 25<sup>2</sup></p>
<p style="text-align:center;">49 + 576 = 625</p>
<p style="text-align:center;">625 = 625</p>
<p>This triangle is a right triangle!</p>
<p>In a bind where a right triangle is involved? Try out the Pythagorean Theorem and see if it helps!</p>
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		<title>Finding the LCM(Least Common Multiple) by Prime Factorization</title>
		<link>http://topcodes.wordpress.com/2009/11/01/finding-the-lcmleast-common-multiple-by-prime-factorization/</link>
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		<pubDate>Sun, 01 Nov 2009 16:34:14 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
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		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 02/11/09 */ We’re going to find the LCM for 12 and 16. So we’ll start by finding the prime factors for both numbers. 12 factors to 2 * 2 * 3 16 factors to 2 * 2 [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=109&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 02/11/09<br />
*/</p>
<p>We’re going to find the LCM for 12 and 16. So we’ll start by finding the prime factors for both numbers.</p>
<p style="text-align:center;">12 factors to 2 * 2 * 3</p>
<p style="text-align:center;">16 factors to 2 * 2 * 2 * 2</p>
<p>Both 12 and 16 have two 2s in their list of factors, so we’ll ignore those. That leaves us with the following factors.</p>
<p style="text-align:center;">12: 3</p>
<p style="text-align:center;">16: 2 * 2</p>
<p>To find the least common multiple, we multiply the original number by the remaining factors of the other number.</p>
<p style="text-align:center;">12 * 2 * 2</p>
<p style="text-align:center;">16 * 3</p>
<p>If you multiply both lines out, you’ll find they both equal 48.  The least common multiple for12 and 16 is 48.</p>
<p>You’ll notice this took a lot less work than the other LCM method, so you might want to try it out yourself the next time you’re staring down a page full of LCM questions.</p>
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		<title>Finding GCD(Greatest Common Divisor) by Prime Factorization</title>
		<link>http://topcodes.wordpress.com/2009/11/01/finding-gcdgreatest-common-divisor-by-prime-factorization/</link>
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		<pubDate>Sun, 01 Nov 2009 16:26:31 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Topic Discussion]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/?p=102</guid>
		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 02/11/09 */ A prime number is any number that can be divided only by itself and 1. Some people find this a more useful way to find common denominators,and it can actually make simplifying radical expressions much [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=102&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 02/11/09<br />
*/</p>
<p>A prime number is any number that can be divided only by itself and 1. Some people find this a more useful way to find common denominators,and it can actually make simplifying radical expressions much simpler.To start factoring a number to its primes, we need to either apply the multiplication facts or the rules of divisibility to it.</p>
<p>Let’s use 72 for this example. 72 is 8 * 9.</p>
<p style="text-align:center;">72<br />
/\<br />
8 9</p>
<p>Neither 8 nor 9 is prime, so we’re going to factor both of them. We know that 8 is 4 * 2; and 9 is 3 * 3, so let’s add those to our factor tree.</p>
<p style="text-align:center;">72<br />
/ \<br />
8   9<br />
/\  /\<br />
2 4  3 3</p>
<p>Now we’re getting somewhere! Both 2 and 3 are prime, leaving us only the 4 to factor. The factor tree looks like this now.</p>
<p style="text-align:center;">72<br />
/ \<br />
8   9<br />
/ \  /\<br />
<strong> 2</strong> 4  <strong>3</strong> <strong>3</strong><br />
/\<br />
<strong> 2</strong> <strong>2</strong></p>
<p>I’ve bolded the prime numbers at the end of each branch so we can see them clearly. The prime factorization of 72 is 2 * 2 * 2 * 3 * 3.</p>
<p>If you use this method to find GCFs, then you’ll need to find all the primes both numbers have in common and multiply them back together. For example, if you were comparing 72 to 12, you’d find that both numbers have two 2s and a 3 in their list of prime factors. 2 * 2 * 3 equals 12, so 12 would be the GCF for 12 and 72.</p>
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		<title>Finding GCD(Greatest Common Divisor) of two integers</title>
		<link>http://topcodes.wordpress.com/2009/11/01/finding-gcdgreatest-common-divisor-of-two-integers-2/</link>
		<comments>http://topcodes.wordpress.com/2009/11/01/finding-gcdgreatest-common-divisor-of-two-integers-2/#comments</comments>
		<pubDate>Sun, 01 Nov 2009 14:54:02 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Topic Discussion]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/?p=94</guid>
		<description><![CDATA[/* Topic Submitted by :  Rafiul Sabbir Dept. : CSE Institution : United International University Submitted at : 01/11/09 */ Another Algorithm finding gcd (x, y) step 1: find the prime factors of x step 2: find the prime factors of y step 3: multiply the common prime factors of x and y Example : [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=94&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Rafiul Sabbir<br />
Dept. : CSE<br />
Institution : United International University<br />
Submitted at : 01/11/09<br />
*/</p>
<p>Another Algorithm finding gcd (x, y)<br />
step 1: find the prime factors of x<br />
step 2: find the prime factors of y<br />
step 3: multiply the common prime factors of x and y</p>
<p>Example :<br />
gcd (60, 24)<br />
prime factors of 60 = 2 * 2 * 3 * 5<br />
prime factors of 24 = 2 * 2 * 2 * 3<br />
common prime factors = 2, 2, 3<br />
multiply them = 2 * 2 * 3 = 12</p>
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		<title>Finding GCD(Greatest Common Divisor) of two integers</title>
		<link>http://topcodes.wordpress.com/2009/11/01/finding-gcdgreatest-common-divisor-of-two-integers/</link>
		<comments>http://topcodes.wordpress.com/2009/11/01/finding-gcdgreatest-common-divisor-of-two-integers/#comments</comments>
		<pubDate>Sun, 01 Nov 2009 14:46:10 +0000</pubDate>
		<dc:creator>topcodes</dc:creator>
				<category><![CDATA[Topic Discussion]]></category>

		<guid isPermaLink="false">http://topcodes.wordpress.com/?p=89</guid>
		<description><![CDATA[/* Topic Submitted by :  Gultu Dept. : CTE Institution : United International University Submitted at : 01/11/09 */ Find the greatest common divisor (gcd) of two integers Euclid’s algorithm: // most efficient gcd (x, y) { step 1: if y = 0, return x. otherwise goto step 2 step 2: gcd (y, x mod [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=topcodes.wordpress.com&amp;blog=9498479&amp;post=89&amp;subd=topcodes&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>/*<br />
Topic Submitted by :  Gultu<br />
Dept. : CTE<br />
Institution : United International University<br />
Submitted at : 01/11/09<br />
*/</p>
<p>Find the greatest common divisor (gcd) of two integers</p>
<p>Euclid’s algorithm: // most efficient</p>
<p>gcd (x, y) {<br />
step 1: if y = 0, return x. otherwise goto step 2<br />
step 2: gcd (y, x mod y) // recursive call<br />
}</p>
<p>Example:<br />
gcd (80, 50)<br />
gcd (50, 80 mod 50) = gcd (50, 30)<br />
gcd (30, 50 mod 30) = gcd (30, 20)<br />
gcd (20, 30 mod 20) = gcd (20, 10)<br />
gcd (10, 20 mod 10) = gcd (10, 0)<br />
return 10.</p>
<p>Algorithm:</p>
<p>1. gcd (x, y) {<br />
if ( y == 0 )<br />
return x;<br />
gcd (y, x % y)<br />
}</p>
<p>2. while ( y &lt;&gt; 0 ) {  // &lt;&gt; = not equals to<br />
a = x % y<br />
x = y<br />
y = a<br />
}<br />
return x</p>
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